<p><strong>Problem description &amp; analysis</strong>:</p>
<p>In the following Excel table, there are duplicate values in column A:</p>
<div class="hn-table">
<table>
<thead>
<tr>
<td></td><td>A</td></tr>
</thead>
<tbody>
<tr>
<td></td><td></td></tr>
<tr>
<td>1</td><td>Fruit</td></tr>
<tr>
<td>2</td><td>Apple</td></tr>
<tr>
<td>3</td><td>Banana</td></tr>
<tr>
<td>4</td><td>Banana</td></tr>
<tr>
<td>5</td><td>Strawberry</td></tr>
</tbody>
</table>
</div><p>Computing task: perform COUNT on each category and concatenate result groups into a string with "+"; if the count is greater than 1, write "x count" after each category. The final result will be like this:</p>
<p><strong>Apple+Bananax2+Strawberry</strong></p>
<p>As shown in the picture below:</p>
<p><img src="https://preview.redd.it/excel-perform-count-on-each-category-and-concatenate-v0-26uden2zai4d1.png?width=752&amp;format=png&amp;auto=webp&amp;s=6c13aa418b16495e6ab881d73a1c047e0296efcf" alt="r/esProc_Desktop - Excel Perform COUNT on Each Category and Concatenate Results into a String" /></p>
<p><strong>Solution</strong>:</p>
<p>Use <strong>SPL XLL</strong> to enter the following formula:</p>
<pre><code class="lang-plaintext">=spl("=?.conj().groups(~;count(1)).(#1 / if(#2&gt;1,$[x] / #2)).concat($[+])",A2:A5)
</code></pre>
<p><strong>Explanation</strong>:</p>
<p>The conj()function concatenates subsets; the groups() function performs grouping &amp; aggregation; with $[], we do not need to escape a string with double quotation marks, and #1 represents the 1<sup>st</sup> field of the table.</p>
<p>SPL XLL is now FREE to download and apply. You can simply click this link to try this solution by yourself to see the results: <a target="_blank" href="http://www.scudata.com/download-Desktop">http://www.scudata.com/download-Desktop</a></p>


**Problem description & analysis**:

In the following Excel table, there are duplicate values in column A:

|  | A |
| --- | --- |
|  |  |
| 1 | Fruit |
| 2 | Apple |
| 3 | Banana |
| 4 | Banana |
| 5 | Strawberry |

Computing task: perform COUNT on each category and concatenate result groups into a string with "+"; if the count is greater than 1, write "x count" after each category. The final result will be like this:

**Apple+Bananax2+Strawberry**

As shown in the picture below:

![r/esProc_Desktop - Excel Perform COUNT on Each Category and Concatenate Results into a String](https://preview.redd.it/excel-perform-count-on-each-category-and-concatenate-v0-26uden2zai4d1.png?width=752&format=png&auto=webp&s=6c13aa418b16495e6ab881d73a1c047e0296efcf align="left")

**Solution**:

Use **SPL XLL** to enter the following formula:

```plaintext
=spl("=?.conj().groups(~;count(1)).(#1 / if(#2>1,$[x] / #2)).concat($[+])",A2:A5)
```

**Explanation**:

The conj()function concatenates subsets; the groups() function performs grouping & aggregation; with $\[\], we do not need to escape a string with double quotation marks, and #1 represents the 1<sup>st</sup> field of the table.

SPL XLL is now FREE to download and apply. You can simply click this link to try this solution by yourself to see the results: [http://www.scudata.com/download-Desktop](http://www.scudata.com/download-Desktop)